-7x^2+39x-50=0

Solution for -7x^2+39x-50=0 equation:

-7x^2+39x-50=0

a = -7; b = 39; c = -50;
Δ = b2-4ac
Δ = 392-4·(-7)·(-50)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-11}{2*-7}=\frac{-50}{-14}
=3+4/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+11}{2*-7}=\frac{-28}{-14}
=+2
$